(* Content-type: application/mathematica *) (*** Wolfram Notebook File ***) (* http://www.wolfram.com/nb *) (* CreatedBy='Mathematica 7.0' *) (*CacheID: 234*) (* Internal cache information: NotebookFileLineBreakTest NotebookFileLineBreakTest NotebookDataPosition[ 145, 7] NotebookDataLength[ 185103, 4974] NotebookOptionsPosition[ 154927, 4216] NotebookOutlinePosition[ 172378, 4540] CellTagsIndexPosition[ 172162, 4532] WindowFrame->Normal*) (* Beginning of Notebook Content *) Notebook[{ Cell[CellGroupData[{ Cell[TextData[StyleBox["Tema 5:\n Resoluci\[OAcute]n de Ecuaciones e \ Inecuaciones.", "Title"]], "Subtitle", CellChangeTimes->{ 3.427102646578125*^9, 3.427517205850881*^9, {3.4281289774375*^9, 3.428128984421875*^9}, {3.459150319*^9, 3.45915032721875*^9}, { 3.459666793890625*^9, 3.45966681515625*^9}}, TextAlignment->Center, TextJustification->0], Cell[CellGroupData[{ Cell["Soluciones exactas y aproximadas de ecuaciones", "Section 1", CellChangeTimes->{{3.459151685328125*^9, 3.459151685671875*^9}}], Cell[TextData[{ StyleBox["Mathematica", FontSlant->"Italic"], " nos permite obtener la soluci\[OAcute]n exacta de muchas ecuaciones y \ sistemas de ecuaciones incluyendo las polin\[OAcute]micas de grado 4 o menor \ con el comando ", StyleBox["Solve", FontSlant->"Italic"], ". La igualdad l\[OAcute]gica viene representada por == (dos iguales \ seguidos). A continuaci\[OAcute]n vamos a obtener informaci\[OAcute]n sobre \ este s\[IAcute]mbolo y el comando ", StyleBox["Solve . 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Para obtener el \ n\[UAcute]mero hay que utilizar el ", StyleBox["operador reemplazamiento, /.", FontWeight->"Bold"], ". En primer lugar", StyleBox[" ", FontWeight->"Bold"], "se guarda el resultado del comando Solve en una variable, por ejemplo s1. \ Despu\[EAcute]s tecleamos la variable que est\[AAcute] delante de la flecha \ en s1, el operador reemplazamiento y el elemento de la lista s1 en el que se \ encuentra el valor num\[EAcute]rico.\nLas siguientes entradas muestran dos \ casos distintos, el primero con una \[UAcute]nica soluci\[OAcute]n y el \ segundo con varias." }], "Text", CellChangeTimes->{{3.427518123285643*^9, 3.427518162364581*^9}, { 3.45915173184375*^9, 3.459151796625*^9}, {3.459151860859375*^9, 3.459152055859375*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"s1", "=", RowBox[{"Solve", "[", RowBox[{ FractionBox[ RowBox[{ SuperscriptBox["x", "2"], "+", RowBox[{"3", "x"}], "+", "2"}], RowBox[{"x", "+", "2"}]], "==", "0"}], "]"}]}]], "Input", CellChangeTimes->{3.457929408078125*^9}], Cell[BoxData[ RowBox[{"{", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "1"}]}], "}"}], "}"}]], "Output", CellChangeTimes->{3.459151833265625*^9, 3.461566836375*^9, 3.46979518115625*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"x", "/.", RowBox[{"s1", "[", RowBox[{"[", "1", "]"}], "]"}]}]], "Input", CellChangeTimes->{3.45792942475*^9, 3.45915192275*^9}], Cell[BoxData[ RowBox[{"-", "1"}]], "Output", CellChangeTimes->{3.459152060703125*^9, 3.461566836375*^9, 3.469795181203125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"s2", "=", RowBox[{"Solve", "[", RowBox[{ RowBox[{ SuperscriptBox["x", "3"], "-", SuperscriptBox["x", "2"], "+", "2"}], "==", "0"}], "]"}]}]], "Input", CellChangeTimes->{3.4579294529375*^9}], Cell[BoxData[ RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "1"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"1", "-", "\[ImaginaryI]"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"1", "+", "\[ImaginaryI]"}]}], "}"}]}], "}"}]], "Output", CellChangeTimes->{3.459152062328125*^9, 3.461566836390625*^9, 3.469795181234375*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"x1", "=", RowBox[{"x", "/.", RowBox[{"s2", "[", RowBox[{"[", "1", "]"}], "]"}]}]}]], "Input"], Cell[BoxData[ RowBox[{"-", "1"}]], "Output", CellChangeTimes->{3.459152065265625*^9, 3.461566836390625*^9, 3.469795181265625*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"x2", "=", RowBox[{"x", "/.", RowBox[{"s2", "[", RowBox[{"[", "2", "]"}], "]"}]}]}]], "Input"], Cell[BoxData[ RowBox[{"1", "-", "\[ImaginaryI]"}]], "Output", CellChangeTimes->{3.45915206634375*^9, 3.461566836390625*^9, 3.4697951813125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"x3", "=", RowBox[{"x", "/.", RowBox[{"s2", "[", RowBox[{"[", "3", "]"}], "]"}]}]}]], "Input", CellChangeTimes->{{3.45792946490625*^9, 3.457929470140625*^9}}], Cell[BoxData[ RowBox[{"1", "+", "\[ImaginaryI]"}]], "Output", CellChangeTimes->{3.459152067046875*^9, 3.46156683640625*^9, 3.46979518134375*^9}] }, Open ]], Cell[TextData[{ "Es importante tener en cuenta que una ecuaci\[OAcute]n como:\n\tsin(x)=a\n\ tiene infinitas soluciones. Al resolver este tipo de ecuaciones ", StyleBox["Mathematica", FontSlant->"Italic"], " necesita utilizar funciones inversas y presenta una soluci\[OAcute]n de \ las posibles y un mensaje indicando que hay m\[AAcute]s soluciones. " }], "Text", CellChangeTimes->{{3.427518087015765*^9, 3.427518092286549*^9}, { 3.427518392570492*^9, 3.4275185523611298`*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ RowBox[{"Sin", "[", "x", "]"}], "\[Equal]", ".5"}], ",", "x"}], "]"}]], "Input", CellChangeTimes->{{3.459152078546875*^9, 3.459152092609375*^9}}], Cell[BoxData[ RowBox[{ RowBox[{"Solve", "::", "\<\"ifun\"\>"}], RowBox[{ ":", " "}], "\<\"\\!\\(\\*StyleBox[\\\"\\\\\\\"Inverse functions are being \ used by \\\\\\\"\\\", \ \\\"MT\\\"]\\)\[NoBreak]\\!\\(\\*StyleBox[\\!\\(Solve\\), \\\"MT\\\"]\\)\ \[NoBreak]\\!\\(\\*StyleBox[\\\"\\\\\\\", so some solutions may not be found; \ use Reduce for complete solution information.\\\\\\\"\\\", \\\"MT\\\"]\\) \\!\ \\(\\*ButtonBox[\\\"\[RightSkeleton]\\\", ButtonStyle->\\\"Link\\\", \ ButtonFrame->None, ButtonData:>\\\"paclet:ref/Solve\\\", ButtonNote -> \ \\\"Solve::ifun\\\"]\\)\"\>"}]], "Message", "MSG", CellChangeTimes->{3.45915209375*^9, 3.4615668366875*^9, 3.469795181421875*^9} ], Cell[BoxData[ RowBox[{"{", RowBox[{"{", RowBox[{"x", "\[Rule]", "0.5235987755982989`"}], "}"}], "}"}]], "Output", CellChangeTimes->{3.45915209375*^9, 3.461566836703125*^9, 3.469795181453125*^9}] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 2\nHallar una soluci\[OAcute]n de la ecuaci\[OAcute]n: ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ RowBox[{"Cos", "(", "x", ")"}], "-", RowBox[{"2", RowBox[{"Sen", "(", RowBox[{"2", "x"}], ")"}]}]}], " ", "=", " ", "0"}], TraditionalForm]]] }], "Subsection", CellChangeTimes->{{3.4579295895*^9, 3.4579296050625*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"Cos", "[", "x", "]"}], "-", RowBox[{"2", " ", RowBox[{"Sin", "[", RowBox[{"2", "x"}], "]"}]}]}], "==", "0"}], ",", "x"}], "]"}]], "Input", CellChangeTimes->{{3.457929481953125*^9, 3.4579295766875*^9}}], Cell[BoxData[ RowBox[{ RowBox[{"Solve", "::", "\<\"ifun\"\>"}], RowBox[{ ":", " "}], "\<\"\\!\\(\\*StyleBox[\\\"\\\\\\\"Inverse functions are being \ used by \\\\\\\"\\\", \ \\\"MT\\\"]\\)\[NoBreak]\\!\\(\\*StyleBox[\\!\\(Solve\\), \\\"MT\\\"]\\)\ \[NoBreak]\\!\\(\\*StyleBox[\\\"\\\\\\\", so some solutions may not be found; \ use Reduce for complete solution information.\\\\\\\"\\\", \\\"MT\\\"]\\) \\!\ \\(\\*ButtonBox[\\\"\[RightSkeleton]\\\", ButtonStyle->\\\"Link\\\", \ ButtonFrame->None, ButtonData:>\\\"paclet:ref/Solve\\\", ButtonNote -> \ \\\"Solve::ifun\\\"]\\)\"\>"}]], "Message", "MSG", CellChangeTimes->{3.461566836765625*^9, 3.469795181515625*^9}], Cell[BoxData[ RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", FractionBox["\[Pi]", "2"]}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", FractionBox["\[Pi]", "2"]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"ArcSin", "[", FractionBox["1", "4"], "]"}]}], "}"}]}], "}"}]], "Output", CellChangeTimes->{3.461566836765625*^9, 3.46979518153125*^9}] }, Open ]], Cell[TextData[{ "\nCon el comando Solve se pueden resolver tambi\[EAcute]n sistemas de \ ecuaciones, que deber\[AAcute]n ir entre llaves. Si no se especifica nada m\ \[AAcute]s ", StyleBox["Mathematica", FontSlant->"Italic"], " intentar\[AAcute] resolver en todas las variables que aparezcan, pero se \ puede indicar tambi\[EAcute]n en qu\[EAcute] variables se desea la soluci\ \[OAcute]n, encerr\[AAcute]ndolas tambi\[EAcute]n entre llaves.\nDel mismo \ modo que en caso de una \[UAcute]nica ecuaci\[OAcute]n, se puede poner un \ nombre a la soluci\[OAcute]n del sistema que da ", StyleBox["Mathematica", FontSlant->"Italic"], " y utilizar este nombre y el operador reemplazamiento /. .\nSi ", StyleBox["Mathematica", FontSlant->"Italic"], " devuelve como soluci\[OAcute]n : { }(conjunto vacio) esto indica que el \ sistema no tiene soluci\[OAcute]n, es decir, que es incompatible." }], "Text", CellChangeTimes->{{3.427518599312585*^9, 3.427518600356352*^9}, 3.457931466421875*^9, 3.4591521110625*^9}, TextAlignment->Left, TextJustification->1] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 3\nResolver los sistemas:\na) ", Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", RowBox[{"2", "x"}], "-", "y", "+", "1"}], "=", "0"}], ",", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", RowBox[{"2", SuperscriptBox["y", "2"]}]}], "=", "2"}]}]]], " .\nb) ", Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{ FractionBox[ SuperscriptBox["x", "2"], "4"], "-", FractionBox[ SuperscriptBox["y", "2"], "16"]}], "=", "1"}], ",", RowBox[{"y", "=", "kx"}]}]]], " ." }], "Subsection", CellChangeTimes->{{3.45792968884375*^9, 3.457929726125*^9}, { 3.4591521940625*^9, 3.4591522218125*^9}, {3.45915238996875*^9, 3.459152391*^9}, {3.459152624390625*^9, 3.459152633640625*^9}}], Cell[CellGroupData[{ Cell["a)", "Subsubsection", CellChangeTimes->{{3.4591527520625*^9, 3.45915275321875*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Solve", "[", RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", RowBox[{"2", "x"}], "-", "y", "+", "1"}], "\[Equal]", "0"}], ",", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", RowBox[{"2", SuperscriptBox["y", "2"]}]}], "\[Equal]", "2"}]}], "}"}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.4579297399375*^9, 3.457929772328125*^9}, { 3.459152167546875*^9, 3.4591521844375*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{"y", "\[Rule]", "1.`"}], ",", RowBox[{"x", "\[Rule]", "0.`"}]}], "}"}], ",", RowBox[{"{", RowBox[{ RowBox[{"y", "\[Rule]", "0.15729810613837605`"}], ",", RowBox[{"x", "\[Rule]", "1.3966082527360921`"}]}], "}"}], ",", RowBox[{"{", RowBox[{ RowBox[{"y", "\[Rule]", RowBox[{ RowBox[{"-", "1.0786490530691877`"}], "-", RowBox[{"0.6525757632523721`", " ", "\[ImaginaryI]"}]}]}], ",", RowBox[{"x", "\[Rule]", RowBox[{"1.301695873631954`", "\[InvisibleSpace]", "-", RowBox[{"1.0815125765499614`", " ", "\[ImaginaryI]"}]}]}]}], "}"}], ",", RowBox[{"{", RowBox[{ RowBox[{"y", "\[Rule]", RowBox[{ RowBox[{"-", "1.0786490530691877`"}], "+", RowBox[{"0.6525757632523721`", " ", "\[ImaginaryI]"}]}]}], ",", RowBox[{"x", "\[Rule]", RowBox[{"1.301695873631954`", "\[InvisibleSpace]", "+", RowBox[{"1.0815125765499614`", " ", "\[ImaginaryI]"}]}]}]}], "}"}]}], "}"}]], "Output", CellChangeTimes->{3.459152186*^9, 3.4615668370625*^9, 3.469795181625*^9}] }, Open ]], Cell["\<\ De las cuatro soluciones que se obtienen s\[OAcute]lamente las dos primeras \ corresponden a valores reales. Vamos a comprobar gr\[AAcute]ficamente que las \ dos curvas se cortan en los dos puntos correspondientes a las dos primeras \ raices.\ \>", "Text", CellChangeTimes->{{3.45915225303125*^9, 3.459152331109375*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"ContourPlot", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", RowBox[{"2", "x"}], "-", "y", "+", "1"}], "\[Equal]", "0"}], ",", RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", RowBox[{"2", SuperscriptBox["y", "2"]}]}], "\[Equal]", "2"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "2"}], ",", "2"}], "}"}], ",", RowBox[{"{", RowBox[{"y", ",", RowBox[{"-", "2"}], ",", "2"}], "}"}], ",", RowBox[{"Axes", "\[Rule]", "True"}], ",", RowBox[{"Frame", "\[Rule]", "None"}]}], "]"}]], "Input", CellChangeTimes->{{3.45793006015625*^9, 3.45793012515625*^9}, { 3.45915223184375*^9, 3.459152236296875*^9}}], Cell[BoxData[ GraphicsBox[GraphicsComplexBox[CompressedData[" 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El resultado se puede interpretar como \"despejar la \ variable que se indica\" ." }], "Text", CellChangeTimes->{{3.45915328353125*^9, 3.45915328728125*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Solve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "+", RowBox[{"2", "x", "*", "y"}], "-", RowBox[{"y", "^", "2"}]}], "\[Equal]", "1"}], ",", "x"}], "]"}]], "Input", CellChangeTimes->{{3.459153299234375*^9, 3.45915331534375*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{ RowBox[{"-", "y"}], "-", SqrtBox[ RowBox[{"1", "+", RowBox[{"2", " ", SuperscriptBox["y", "2"]}]}]]}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{ RowBox[{"-", "y"}], "+", SqrtBox[ RowBox[{"1", "+", RowBox[{"2", " ", SuperscriptBox["y", "2"]}]}]]}]}], "}"}]}], "}"}]], "Output", CellChangeTimes->{3.459153316421875*^9, 3.461566842671875*^9, 3.469795182125*^9}] }, Open ]] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Eliminando una inc\[OAcute]gnita en una ecuaci\[OAcute]n o un conjunto de \ ecuaciones polin\[OAcute]micas\ \>", "Section 1", CellChangeTimes->{{3.4275204146726933`*^9, 3.427520446417678*^9}}], Cell[TextData[{ "El comando ", StyleBox["Eliminate[ecuaciones, variables]", FontWeight->"Bold"], " nos permite eliminar o despejar una o varias inc\[OAcute]gnitas entre \ varias ecuaciones polin\[OAcute]micas. Las ecuaciones deber\[AAcute]n ir \ entre llaves y separadas por comas o bien ligadas con el s\[IAcute]mbolo ", StyleBox["&&", FontWeight->"Bold"], ", que es el operador l\[OAcute]gico ", StyleBox["And", FontWeight->"Bold"] }], "Text", CellChangeTimes->{{3.42751942053434*^9, 3.427519473993185*^9}, { 3.4275195778419867`*^9, 3.427519582283784*^9}, {3.427519681210767*^9, 3.427519738460105*^9}, 3.4277779430396233`*^9}], Cell[CellGroupData[{ Cell["\<\ Ejemplo 5 Eliminar z en las ecuaciones, \t2x+3y+4z=1 \t9x+8y+7z=2\ \>", "Subsection", CellChangeTimes->{{3.427519495121357*^9, 3.4275195171945143`*^9}, { 3.427519594378459*^9, 3.427519673742333*^9}, {3.427778038166032*^9, 3.4277780387110147`*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Eliminate", "[", RowBox[{ RowBox[{"{", RowBox[{ RowBox[{ RowBox[{ RowBox[{"2", "x"}], "+", RowBox[{"3", "y"}], "+", RowBox[{"4", "z"}]}], "\[Equal]", "1"}], ",", RowBox[{ RowBox[{ RowBox[{"9", "x"}], "+", RowBox[{"8", "y"}], "+", RowBox[{"7", "z"}]}], "\[Equal]", "2"}]}], "}"}], ",", "z"}], "]"}]], "Input", CellChangeTimes->{{3.4275203373511477`*^9, 3.42752035342028*^9}}, CellID->539162013], Cell[BoxData[ RowBox[{ RowBox[{"1", "-", RowBox[{"11", " ", "y"}]}], "\[Equal]", RowBox[{"22", " ", "x"}]}]], "Output", CellChangeTimes->{3.46156684278125*^9, 3.469795182171875*^9}] }, Open ]] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Aproximaci\[OAcute]n num\[EAcute]rica de la soluci\[OAcute]n de una ecuaci\ \[OAcute]n\ \>", "Section 1"], Cell[TextData[{ "Cuando es imposible resolver anal\[IAcute]ticamente o de forma exacta una \ ecuaci\[OAcute]n, ", StyleBox["Mathematica", FontSlant->"Italic"], " dispone de varios comando que permiten obtener una soluci\[OAcute]n \ aproximada. Estos comandos son FindRoot, NRoots y NSolve. El comando NRoots \ sirve ecuaciones polin\[OAcute]micas. El comando FindRoot necesita una \ aproximaci\[OAcute]n inicial a partir de la cual realiza el c\[AAcute]lculo \ de la raiz. Para obtener esta aproximaci\[OAcute]n inicial lo mejor, siempre \ que sea posible es realizar las gr\[AAcute]ficas correspondientes." }], "Text", CellChangeTimes->{{3.427520496835723*^9, 3.427520497846869*^9}, 3.45793148690625*^9, {3.459153173125*^9, 3.45915324434375*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 6\nObtener las soluciones aproximadas de la ecuaci\[OAcute]n:\n", Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "=", "0"}]], CellChangeTimes->{{3.457930757875*^9, 3.457930819546875*^9}}] }], "Subsection", CellChangeTimes->{ 3.427520516564314*^9, {3.427778043658533*^9, 3.42777804414909*^9}, { 3.45793073315625*^9, 3.45793074875*^9}, {3.4579308281875*^9, 3.457930833765625*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"NRoots", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", "x"}], "]"}]], "Input", CellChangeTimes->{3.4579306985625*^9, 3.45793073796875*^9, 3.457930831171875*^9}], Cell[BoxData[ RowBox[{ RowBox[{"x", "\[Equal]", RowBox[{"-", "1.1337562278058309`"}]}], "||", RowBox[{"x", "\[Equal]", RowBox[{"-", "0.6247424245153483`"}]}], "||", RowBox[{"x", "\[Equal]", RowBox[{ RowBox[{"-", "0.5819976870410729`"}], "-", RowBox[{"1.5010745352317583`", " ", "\[ImaginaryI]"}]}]}], "||", RowBox[{"x", "\[Equal]", RowBox[{ RowBox[{"-", "0.5819976870410729`"}], "+", RowBox[{"1.5010745352317583`", " ", "\[ImaginaryI]"}]}]}], "||", RowBox[{"x", "\[Equal]", "0.6121950386886468`"}], "||", RowBox[{"x", "\[Equal]", RowBox[{"1.155149493857339`", "\[InvisibleSpace]", "-", RowBox[{"0.667166713644494`", " ", "\[ImaginaryI]"}]}]}], "||", RowBox[{"x", "\[Equal]", RowBox[{"1.155149493857339`", "\[InvisibleSpace]", "+", RowBox[{"0.667166713644494`", " ", "\[ImaginaryI]"}]}]}]}]], "Output", CellChangeTimes->{3.461566842828125*^9, 3.469795182203125*^9}] }, Open ]], Cell[TextData[{ "El s\[IAcute]mbolo || de la respuesta representa al operador l\[OAcute]gico \ \"", StyleBox["OR", FontWeight->"Bold"], "\"" }], "Text", CellChangeTimes->{{3.4275205297720957`*^9, 3.427520560155941*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"?", "||"}]], "Input"], Cell[BoxData[ RowBox[{ StyleBox["\<\"\!\(\*RowBox[{SubscriptBox[StyleBox[\\\"e\\\", \\\"TI\\\"], \ StyleBox[\\\"1\\\", \\\"TR\\\"]], \\\"||\\\", \ SubscriptBox[StyleBox[\\\"e\\\", \\\"TI\\\"], StyleBox[\\\"2\\\", \ \\\"TR\\\"]], \\\"||\\\", StyleBox[\\\"\[Ellipsis]\\\", \\\"TR\\\"]}]\) is \ the logical OR function. It evaluates its arguments in order, giving True \ immediately if any of them are True, and False if they are all False. \"\>", "MSG"], "\[NonBreakingSpace]", ButtonBox[ StyleBox["\[RightSkeleton]", "SR"], Active->True, BaseStyle->"Link", ButtonData->"paclet:ref/Or"]}]], "Print", "PrintUsage", CellChangeTimes->{3.46979518246875*^9}, CellTags->"Info3469798782-9119275"] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"NSolve", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", "x"}], "]"}]], "Input", CellChangeTimes->{3.457930746890625*^9, 3.45793084459375*^9}], Cell[BoxData[ RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "1.1337562278058309`"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "0.6247424245153483`"}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{ RowBox[{"-", "0.5819976870410729`"}], "-", RowBox[{"1.5010745352317583`", " ", "\[ImaginaryI]"}]}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{ RowBox[{"-", "0.5819976870410729`"}], "+", RowBox[{"1.5010745352317583`", " ", "\[ImaginaryI]"}]}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", "0.6121950386886468`"}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"1.155149493857339`", "\[InvisibleSpace]", "-", RowBox[{"0.667166713644494`", " ", "\[ImaginaryI]"}]}]}], "}"}], ",", RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"1.155149493857339`", "\[InvisibleSpace]", "+", RowBox[{"0.667166713644494`", " ", "\[ImaginaryI]"}]}]}], "}"}]}], "}"}]], "Output", CellChangeTimes->{3.461566843625*^9, 3.4697951825625*^9}] }, Open ]], Cell[TextData[{ "El comando ", StyleBox["FindRoot[f, {x,", FontWeight->"Bold"], Cell[BoxData[ FormBox[ SubscriptBox["x", "0"], TraditionalForm]], FontWeight->"Bold"], StyleBox["}] ", FontWeight->"Bold"], "obtiene la soluci\[OAcute]n num\[EAcute]rica de una ecuaci\[OAcute]n o un \ sistema. Este comando implementa el m\[EAcute]todo num\[EAcute]rico de Newton \ - Raphson y necesita una aproximaci\[OAcute]n inicial, que ir\[AAcute] entre \ llaves con la inc\[OAcute]gnita separada por una coma. Para tener idea del \ valor de la aproximaci\[OAcute]n inicial conviene hacer una representaci\ \[OAcute]n gr\[AAcute]fica.\nVamos a obtener mediante este comando las raices \ reales de la ecuaci\[OAcute]n anterior. Para ello, en primer lugar, \ representamos gr\[AAcute]ficamente la funci\[OAcute]n polin\[OAcute]mica." }], "Text", CellChangeTimes->{{3.4275205911892776`*^9, 3.427520593457205*^9}, { 3.4275206615213537`*^9, 3.4275208105454903`*^9}, {3.427520850282934*^9, 3.427521025224519*^9}}, TextAlignment->Left, TextJustification->1.], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Plot", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "2"}], ",", "2"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.457930757875*^9, 3.457930819546875*^9}}], Cell[BoxData[ GraphicsBox[{{}, {}, {Hue[0.67, 0.6, 0.6], LineBox[CompressedData[" 1:eJwVl3c41e8bx4XIFmVnhZCVlZGejxIqm6SSSlKpkIyKMpJEhC9FIdGQZESR 1H2yZ/ZemVnnOMtxCOd3fn99rtf13Nf7ns/nuh85dx+HS6wsLCzkLSws//9u PeBV7cq3CumuHJ+DLuvj8p86V1qN08GBJD+WsVcPV1dW5oAN02FYcP+T0W16 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Tres buenas aproximaciones para estas tres raices son : -2.5, -1 y 2.\ \>", "Text", CellChangeTimes->{{3.427521053818596*^9, 3.4275210978990393`*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindRoot", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{"-", "1"}]}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.4579308600625*^9, 3.457930865140625*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "1.1337562278058309`"}]}], "}"}]], "Output", CellChangeTimes->{3.461566844703125*^9, 3.469795182671875*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindRoot", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{ RowBox[{"-", "1"}], "/", "2"}]}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.457930876890625*^9, 3.457930882546875*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{"-", "0.6247424245153483`"}]}], "}"}]], "Output", CellChangeTimes->{3.461566844765625*^9, 3.469795182703125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindRoot", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", "1"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.457930889328125*^9, 3.4579308955625*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{"x", "\[Rule]", "0.6121950386886468`"}], "}"}]], "Output", CellChangeTimes->{3.461566844796875*^9, 3.469795182734375*^9}] }, Open ]], Cell["\<\ Tambien podemos utilizar el comando para obtener una raiz compleja aunque en \ este caso puede resultar m\[AAcute]s dif\[IAcute]cil dar una buena aproximaci\ \[OAcute]n inicial.\ \>", "Text", CellChangeTimes->{{3.42752118449511*^9, 3.427521235393392*^9}, { 3.427521295085634*^9, 3.427521300775399*^9}, {3.427521398434411*^9, 3.427521405231832*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindRoot", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "7"}], "-", RowBox[{"2", SuperscriptBox["x", "4"]}], "+", RowBox[{"6", SuperscriptBox["x", "2"]}], "-", "2"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", RowBox[{ RowBox[{"-", "0.5"}], "-", RowBox[{"1.5", "I"}]}]}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.4579309128125*^9, 3.457930924203125*^9}}], Cell[BoxData[ RowBox[{"{", RowBox[{"x", "\[Rule]", RowBox[{ RowBox[{"-", "0.5819976870410729`"}], "-", RowBox[{"1.5010745352317583`", " ", "\[ImaginaryI]"}]}]}], "}"}]], "Output", CellChangeTimes->{3.461566845171875*^9, 3.46979518284375*^9}] }, Open ]], Cell[TextData[{ "La soluci\[OAcute]n que nos da este comando es del mismo tipo que la que \ proporciona Solve, es decir, no es un n\[UAcute]mero, sino que ", StyleBox["Mathematica", FontSlant->"Italic"], " nos dice qu\[EAcute] valor hay que asignar a la inc\[OAcute]gnita para \ tener la soluci\[OAcute]n. Para sacar el n\[UAcute]mero hay que utilizar el \ operador reemplazamiento." }], "Text", CellChangeTimes->{{3.42752135026117*^9, 3.427521378930348*^9}, { 3.4275214221551657`*^9, 3.427521507567422*^9}}] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Ejemplo 7 Aproximar las soluciones positivas de la ecuaci\[OAcute]n: cos(x)-x = 0\ \>", "Subsection", CellChangeTimes->{{3.427521316509486*^9, 3.427521316910631*^9}, { 3.427778070930575*^9, 3.427778071729713*^9}}], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{"Clear", "[", "f", "]"}], "\n", RowBox[{ RowBox[{ RowBox[{"f", "[", "x_", "]"}], "=", RowBox[{ RowBox[{"Cos", "[", "x", "]"}], "-", "x"}]}], ";"}], "\n", RowBox[{"Plot", "[", RowBox[{ RowBox[{"f", "[", "x", "]"}], ",", RowBox[{"{", RowBox[{"x", ",", "0", ",", "1"}], "}"}]}], "]"}]}], "Input"], Cell[BoxData[ GraphicsBox[{{}, {}, {Hue[0.67, 0.6, 0.6], LineBox[CompressedData[" 1:eJwtlH8803kcx/08ui5G57oR+dnJj7hOnVDvrnWmDT2wWiqlMtVSJ+lc5R6s 6EqJx53UxVgI5VjdRi702Wm5Bydaw7R9NzOzxmZfdX4crtzu8bg/3o/X4/3H 6/XX6/V0O/RNLMPMxMQkynj/KYWhFQnGdm6+sWrp9OIiDhYkx9QhYhBEeYru Z77D4YvyW6U84jb4M3DF2rl5HKjPJb+yiTSgHvZgv5nGgZ402/YjMQlsdoQ5 K3U4yAN+IOUT06EoMu0uT4IDx2HHpTxiDpQV2A4EcXFgWfM+u0Isgr/XOT4u T8Bhd/wd7uSbKvhHx2F+cN8ASxdZ+8guXMh8NkNfeD8BXjEG7dOrfKhhuk95 0yYgo2cj3Jr6Dd6yfML23tTDCr6dwtQUwY3zS2oUIzpoUpG6e8PawaA0W9Xp rIN2JtspXi+E5otCyyb6OEyv3mRbf+IPYAbk17eVjIHZXB3ByasLgsuij5zo 1sKGxcSmuIZucMGLH3GstNCdE9TT4dMLFIa7VS3pNawq1M3dM7yAPTNHD1Yc 14BudkjRH/gSmkmhqZqyUagab+myuS6G9t63z/Pa1GDjXIOr1X1Qe60tRIqN wLVjjckczwHwM3Hy2Gw9AjNb6tRHsyRAjuh8F+eigvR1Qv4nTwfB8p2bq3bL MAw1CK+K3KSQonMqrIxSwgKzr2TNORnQHeOLR5sU4PuV1fvkFgzYmhJzhwkM yBVuRx6uUMA9a0J69IwUMpwPuA/vG4Is6q4UveMr8NPvXCox5tSWG8zjSRJY bjtpLZxXAm1K8KRiUz9YoBKuR+kwaKJ7VWKaGI4HtbxaQlXBfcb0uCFMBHXb D3GezKjAVRN0MSWmB6Z1jgRN8QikY7bBfYwuaIwjmxdtU4P2ep9ilNgBWRG5 5XyNGraFVzsd+6gd3OSUwcrcUcjO+Yugt2+FkC9ziojrNJDY8MF5ZgQP9rn0 zpmKNUDIMVRZmlbDdFe+KpX1GrLjqO2fL8uCWxb702M9tZCttGxhJ91GyxWN FWZCLQTSZbuDHRqQ5fcs2sZTYzD4uwObRG5GJvf2c1X246COuJKXkClAabe5 +fbt45Dq28+3D3uG2nwvW9ud1AGHQM9g4J3IjpLmd8FGD36XrmtT9vQgzP+F +GyrHiheyprJYhF6UAae6v0TQCCuTO6RiVECd4Ods7Gn8wOlm5YRB1B27h0W ZuxxGZW31v3qIKrXOpfYROJAc/TguEqk6DI7N1ERjUPmFQaJOSxFSbETXg0x xp1UkP35Oila2dr6IIqOQ+nks74IExnKK9jbce0QDifra0+dWSNDRzf8/ObD s0Z/2lup7LwMued8HGFVjcPqqUEfuSuG3gdnLpPU4oD1ehcG+GLo1cTIy+o6 HPaEToZcWI+hQjovIfyh8b8tSPSmYGjRJ/Z0bisOv4Qf1mecxhAmKigzF+MQ viR/waMDQ82XZg+L+3H41nued+4FhopCD6ypHDTmL2x/KJJiiHp3LX+rAofH Z1LOZeMYevzd807WGA6BNx59PfypHBX7ry+I0ePgt3G9Z4iHHJ1SldLccBxS Jynkn/zlyDsyZUgwZeTAZuLe8K1yZGHaV1U4i0PyakTlRMqRsjGUmWjkTpFQ kj2/S45amZUBgUYubRXEz9MOytHN/7lFEYQ2c4/L0b+Bf4b0 "]]}}, AspectRatio->NCache[GoldenRatio^(-1), 0.6180339887498948], Axes->True, AxesOrigin->{0, 0}, PlotRange->{{0, 1}, {-0.45969765655081984`, 0.9999999795918365}}, PlotRangeClipping->True, PlotRangePadding->{ Scaled[0.02], Scaled[0.02]}]], "Output", CellChangeTimes->{3.461566845203125*^9, 3.469795182890625*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindRoot", "[", RowBox[{ RowBox[{ RowBox[{"f", "[", "x", "]"}], "==", "0"}], ",", RowBox[{"{", RowBox[{"x", ",", "0.7"}], "}"}]}], "]"}]], "Input"], Cell[BoxData[ RowBox[{"{", RowBox[{"x", "\[Rule]", "0.7390851332151608`"}], "}"}]], "Output", CellChangeTimes->{3.46156684521875*^9, 3.46979518290625*^9}] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 8\nAproximar los puntos de intersecci\[OAcute]n de las curvas: \n\ f(x) = log(6x) y g(x)=sen(", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ RowBox[{"5", SuperscriptBox["x", RowBox[{"3", "/", "2"}]]}], ")"}], "+", RowBox[{"5", "/", "4."}]}], TraditionalForm]]] }], "Subsection", CellChangeTimes->{{3.4277781458420353`*^9, 3.427778146726212*^9}, { 3.457931123*^9, 3.457931148296875*^9}}], Cell["\<\ En primer lugar hacemos la representaci\[OAcute]n gr\[AAcute]fica de ambas \ funciones. 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CellChangeTimes->{3.461566845515625*^9, 3.4697951831875*^9}] }, Open ]] }, Open ]] }, Open ]], Cell["\<\ Resoluci\[OAcute]n de ecuaciones e inecuaciones\ \>", "Section 1", CellChangeTimes->{{3.427630357335984*^9, 3.427630369045012*^9}}], Cell[CellGroupData[{ Cell["El comando FindInstance", "Section", CellChangeTimes->{{3.4276969860862103`*^9, 3.4276969916874723`*^9}}], Cell[TextData[{ "Mathematica dispone del comando ", StyleBox["FindInstance ", FontWeight->"Bold"], "que da una soluci\[OAcute]n particular de forma similar al comando ", StyleBox["Solve", FontWeight->"Bold"], ".\nLa sintaxis m\[AAcute]s sencilla es:\n", StyleBox["\tFindInstance[expr, variables]\n", FontWeight->"Bold"], "La soluci\[OAcute]n obtenida en las variables hace verdadera a expr. \n\ Expr. puede contener ecuaciones, inecuaciones y especificaciones de dominio.\n\ Si el argumento es un valor exacto entonces el resultado tambi\[EAcute]n lo \ ser\[AAcute]." }], "Text", CellChangeTimes->{{3.42763037922237*^9, 3.427630465890265*^9}, { 3.427630502827949*^9, 3.4276307594761353`*^9}, {3.4276315123067083`*^9, 3.427631524543754*^9}, {3.427632012845222*^9, 3.4276320172946997`*^9}, 3.45915343459375*^9}], Cell[TextData[{ "Por ejemplo, una soluci\[OAcute]n del conjunto de soluciones que verifican \ el sistema :\n\t", Cell[BoxData[ FormBox[ TagBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"], "+", SuperscriptBox["z", "2"]}], "=", RowBox[{"-", "1"}]}]}, { RowBox[{ SuperscriptBox["z", "2"], "=", RowBox[{ RowBox[{"2", "x"}], "-", RowBox[{"5", "y"}]}]}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], #& ], TraditionalForm]]], "\nse puede obener," }], "Text", CellChangeTimes->{{3.427648945897633*^9, 3.4276490474420967`*^9}, { 3.427649084072817*^9, 3.427649105434977*^9}, {3.4276495612778397`*^9, 3.427649572283721*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindInstance", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "+", RowBox[{"y", "^", "2"}], "+", RowBox[{"z", "^", "2"}]}], "\[Equal]", RowBox[{"-", "1"}]}], "&&", RowBox[{ RowBox[{"z", "^", "2"}], "\[Equal]", RowBox[{ RowBox[{"2", "x"}], "-", RowBox[{"5", " ", "y"}]}]}]}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}]}], "]"}]], "Input", CellChangeTimes->{{3.427630892584937*^9, 3.427630895397917*^9}}, CellID->47420189], Cell[BoxData[ RowBox[{"{", RowBox[{"{", RowBox[{ RowBox[{"x", "\[Rule]", "0"}], ",", RowBox[{"y", "\[Rule]", RowBox[{ FractionBox["1", "2"], " ", RowBox[{"(", RowBox[{"5", "-", SqrtBox["21"]}], ")"}]}]}], ",", RowBox[{"z", "\[Rule]", RowBox[{ RowBox[{"-", "\[ImaginaryI]"}], " ", SqrtBox[ RowBox[{ FractionBox["5", "2"], " ", RowBox[{"(", RowBox[{"5", "-", SqrtBox["21"]}], ")"}]}]]}]}]}], "}"}], "}"}]], "Output", CellChangeTimes->{3.459153448125*^9, 3.461566846546875*^9, 3.469795183390625*^9}] }, Open ]], Cell[TextData[{ "Para obtener una soluci\[OAcute]n real del sistema :\n\t", Cell[BoxData[ FormBox[ TagBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"], "+", SuperscriptBox["z", "2"]}], "\[LessEqual]", "1"}]}, { RowBox[{ RowBox[{"9", SuperscriptBox["z", "3"]}], "=", RowBox[{ RowBox[{"2", "x"}], "-", RowBox[{"5", "y"}], "-", "7"}]}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], #& ], TraditionalForm]]], "\na\[NTilde]adimos la opci\[OAcute]n Reals." }], "Text", CellChangeTimes->{{3.427649589073806*^9, 3.427649711579362*^9}, { 3.459153686859375*^9, 3.459153701296875*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"FindInstance", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "+", RowBox[{"y", "^", "2"}], "+", RowBox[{"z", "^", "2"}]}], "\[LessEqual]", "1"}], "&&", RowBox[{ RowBox[{"9", RowBox[{"z", "^", "3"}]}], "\[Equal]", RowBox[{ RowBox[{"2", "x"}], "-", RowBox[{"5", " ", "y"}], "-", "7"}]}]}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}], ",", "Reals"}], "]"}]], "Input", CellChangeTimes->{{3.427631036493123*^9, 3.427631058437057*^9}}, CellID->60662809], Cell[BoxData[ RowBox[{"{", RowBox[{"{", RowBox[{ RowBox[{"x", "\[Rule]", FractionBox["45", "128"]}], ",", RowBox[{"y", "\[Rule]", RowBox[{"-", FractionBox["1", "2"]}]}], ",", RowBox[{"z", "\[Rule]", RowBox[{"-", FractionBox["3", "4"]}]}]}], "}"}], "}"}]], "Output", CellChangeTimes->{3.4591534546875*^9, 3.461566847265625*^9, 3.46979518346875*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 9\nEncontrar dos soluciones de la inecuaci\[OAcute]n:\n\t", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "\[LessEqual]", "1"}], TraditionalForm]]], " con x<1\nRepresentarlas gr\[AAcute]ficamente para comprobar que verifican \ la incecuaci\[OAcute]n" }], "Subsection", CellChangeTimes->{{3.4276510001136723`*^9, 3.427651002284696*^9}, { 3.427651085390567*^9, 3.4276511705851307`*^9}, {3.427696139274692*^9, 3.42769615353659*^9}, 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Su sintaxis es :\n", StyleBox["\tReduce[expr, variables]\n", FontWeight->"Bold"], "La salida del comando describe matem\[AAcute]ticamente el mismo conjunto \ que expr. Se puede especificar tambi\[EAcute]n el dominio al que debe \ pertener la soluci\[OAcute]n. Los m\[AAcute]s habituales son Integer, Real o \ Complex. \n\nEn las salidas debemos interpretar el s\[IAcute]mbolo && como el \ And l\[OAcute]gico, y el s\[IAcute]mbolo ", "|| como el Or l\[OAcute]gico." }], "Text", CellChangeTimes->{{3.427632020951356*^9, 3.427632110337541*^9}, { 3.427632155921681*^9, 3.427632294898506*^9}, {3.459154053046875*^9, 3.459154115328125*^9}}, TextAlignment->Left, TextJustification->1.], Cell[TextData[{ "El conjunto de valores de x e y que verifican ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], "<", "1"}], TraditionalForm]]] }], "Text", CellChangeTimes->{{3.4276518583111677`*^9, 3.4276519078418713`*^9}, { 3.427651985223126*^9, 3.4276519876316357`*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "+", RowBox[{"y", "^", "2"}]}], "<", "1"}], ",", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}]}], "]"}]], "Input", CellID->15483236], Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{"-", "1"}], "<", "x", "<", "1"}], "&&", RowBox[{ RowBox[{"-", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"]}]]}], "<", "y", "<", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"]}]]}]}]], "Output", CellChangeTimes->{3.461566847796875*^9, 3.469795183640625*^9}] }, Open ]], Cell[TextData[{ "El conjunto de valores de x e y que verifican ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", RowBox[{"7", SuperscriptBox["y", "2"]}]}], "=", "1"}], TraditionalForm]]], " con x>0 e y>0" }], "Text", CellChangeTimes->{{3.427652027849949*^9, 3.427652037314539*^9}, { 3.427652120357567*^9, 3.427652195892223*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "-", RowBox[{"7", RowBox[{"y", "^", "2"}]}]}], "\[Equal]", "1"}], "&&", RowBox[{"x", ">", "0"}], "&&", RowBox[{"y", ">", "0"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "y"}], "}"}], ",", "Reals"}], "]"}]], "Input", CellChangeTimes->{{3.427652001732354*^9, 3.427652015865838*^9}}, CellID->118871955], Cell[BoxData[ RowBox[{ RowBox[{"x", ">", "1"}], "&&", RowBox[{"y", "\[Equal]", FractionBox[ SqrtBox[ RowBox[{ RowBox[{"-", "1"}], "+", SuperscriptBox["x", "2"]}]], SqrtBox["7"]]}]}]], "Output", CellChangeTimes->{3.461566847859375*^9, 3.469795183734375*^9}] }, Open ]], Cell[TextData[{ "El conjunto de valores {x, y, z } reales que verifican ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", "yz"}], " ", "=", " ", "1"}], TraditionalForm]]] }], "Text", CellChangeTimes->{{3.427652704410445*^9, 3.427652771746973*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "-", RowBox[{"y", " ", "z"}]}], "\[Equal]", "1"}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}], ",", "Reals"}], "]"}]], "Input", CellID->758827168], Cell[BoxData[ RowBox[{ RowBox[{"(", RowBox[{ RowBox[{"x", "\[Equal]", RowBox[{"-", "1"}]}], "&&", RowBox[{"y", "\[Equal]", "0"}]}], ")"}], "||", RowBox[{"(", RowBox[{ RowBox[{"x", "\[Equal]", "1"}], "&&", RowBox[{"y", "\[Equal]", "0"}]}], ")"}], "||", RowBox[{"(", RowBox[{ RowBox[{"(", RowBox[{ RowBox[{"y", "<", "0"}], "||", RowBox[{"y", ">", "0"}]}], ")"}], "&&", RowBox[{"z", "\[Equal]", RowBox[{"-", FractionBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"]}], "y"]}]}]}], ")"}]}]], "Output", CellChangeTimes->{3.461566848125*^9, 3.469795183796875*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 10\nDescribir matem\[AAcute]ticamente el conjunto de valores reales \ de {x, y, z} que verifican ", Cell[BoxData[ FormBox[ SuperscriptBox["x", "2"], TraditionalForm]]], "-2y + ", Cell[BoxData[ FormBox[ SuperscriptBox["z", "2"], TraditionalForm]]], "\[LessEqual] 1. " }], "Subsection", CellChangeTimes->{{3.427652885181555*^9, 3.427652933103829*^9}, { 3.4277782844537563`*^9, 3.4277782874792423`*^9}, {3.459153808703125*^9, 3.459153877515625*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "-", RowBox[{"2", "y"}], " ", "+", RowBox[{"z", "^", "2"}]}], "\[LessEqual]", "1"}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}], ",", "Reals"}], "]"}]], "Input", CellID->223254230], Cell[BoxData[ RowBox[{ RowBox[{"(", RowBox[{ RowBox[{"y", "\[Equal]", RowBox[{ FractionBox["1", "2"], " ", RowBox[{"(", RowBox[{ RowBox[{"-", "1"}], "+", SuperscriptBox["x", "2"]}], ")"}]}]}], "&&", RowBox[{"z", "\[Equal]", "0"}]}], ")"}], "||", RowBox[{"(", RowBox[{ RowBox[{"y", ">", RowBox[{ FractionBox["1", "2"], " ", RowBox[{"(", RowBox[{ RowBox[{"-", "1"}], "+", SuperscriptBox["x", "2"]}], ")"}]}]}], "&&", RowBox[{ RowBox[{"-", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"], "+", RowBox[{"2", " ", "y"}]}]]}], "\[LessEqual]", "z", "\[LessEqual]", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"], "+", RowBox[{"2", " ", "y"}]}]]}]}], ")"}]}]], "Output", CellChangeTimes->{3.45915388096875*^9, 3.46156684815625*^9, 3.46979518384375*^9}] }, Open ]], Cell[TextData[{ "La interpretaci\[OAcute]n de este resultado es la siguiente :\n1\.ba) z = 0 \ e y = ", Cell[BoxData[ RowBox[{ FractionBox["1", "2"], " ", RowBox[{"(", RowBox[{ RowBox[{"-", "1"}], "+", SuperscriptBox["x", "2"]}], ")"}]}]], CellChangeTimes->{3.45915388096875*^9}], " con cualquier valor de x.\n\to\n2\.ba) y > ", Cell[BoxData[ RowBox[{ FractionBox["1", "2"], " ", RowBox[{"(", RowBox[{ RowBox[{"-", "1"}], "+", SuperscriptBox["x", "2"]}], ")"}]}]], CellChangeTimes->{3.45915388096875*^9}], "y ", Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{"-", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"], "+", RowBox[{"2", " ", "y"}]}]]}], "\[LessEqual]", "z", "\[LessEqual]", SqrtBox[ RowBox[{"1", "-", SuperscriptBox["x", "2"], "+", RowBox[{"2", " ", "y"}]}]]}], ")"}]], CellChangeTimes->{3.45915388096875*^9}], " con cualquier valor de x." }], "Text", CellChangeTimes->{{3.459153896046875*^9, 3.459154018296875*^9}}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 11\nHallar los valores reales que verifican:\n\t", Cell[BoxData[ FormBox[ TagBox[ StyleBox[ RowBox[{"{", GridBox[{ { RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "+", "yz"}], "=", "1"}]}, { RowBox[{ RowBox[{"x", "+", RowBox[{"2", "y"}]}], "\[LessEqual]", RowBox[{ RowBox[{"3", "z"}], "+", "1"}]}]}, { RowBox[{"xyz", ">", "7"}]} }]}], ShowAutoStyles->False], #& ], TraditionalForm]], "None"], "\t" }], "Subsection", CellChangeTimes->{{3.427653024754302*^9, 3.427653065355845*^9}, { 3.427653866918251*^9, 3.427653913900872*^9}, {3.427778339934308*^9, 3.427778343671247*^9}, {3.459154022546875*^9, 3.459154024140625*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "2"}], "+", RowBox[{"y", " ", "z"}]}], "\[Equal]", "1"}], "&&", RowBox[{ RowBox[{"x", "+", RowBox[{"2", "y"}]}], "\[LessEqual]", RowBox[{ RowBox[{"3", "z"}], "+", "1"}]}], "&&", RowBox[{ RowBox[{"x", " ", "y", " ", "z"}], ">", "7"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}], ",", "Reals"}], "]"}], "//", "N"}]], "Input", CellChangeTimes->{{3.42765282837475*^9, 3.427652828954577*^9}}, CellID->91668569], Cell[BoxData[ RowBox[{ RowBox[{"x", "<", RowBox[{"-", "2.0867453398826665`"}]}], "&&", RowBox[{"y", "<", "0.`"}], "&&", RowBox[{"z", "\[Equal]", FractionBox[ RowBox[{"1.`", "\[InvisibleSpace]", "-", RowBox[{"1.`", " ", SuperscriptBox["x", "2"]}]}], "y"]}]}]], "Output", CellChangeTimes->{3.4591540300625*^9, 3.46156684821875*^9, 3.469795183921875*^9}] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 12\nHallar los valores reales de x e y que verifican:\n\t", Cell[BoxData[ FormBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{ RowBox[{ SuperscriptBox["3", "x"], "-", SuperscriptBox["2", RowBox[{"2", "y"}]]}], "=", "77"}]}, { RowBox[{ RowBox[{ SqrtBox[ SuperscriptBox["3", "x"]], "-", SuperscriptBox["2", "y"]}], "=", "7"}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], TraditionalForm]]] }], "Subsection", CellChangeTimes->{{3.427653024754302*^9, 3.427653065355845*^9}, { 3.427653866918251*^9, 3.427653913900872*^9}, {3.4276539496715517`*^9, 3.4276540065633783`*^9}, {3.427654051648344*^9, 3.427654160589184*^9}, { 3.427696298280943*^9, 3.4276963280219917`*^9}, {3.427696522928464*^9, 3.427696525307588*^9}, {3.427778383648695*^9, 3.4277783865568447`*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", " ", RowBox[{ RowBox[{ RowBox[{ RowBox[{ SuperscriptBox["3", "x"], "-", SuperscriptBox["2", RowBox[{"2", "y"}]]}], "\[Equal]", "77"}], " ", "&&", " ", RowBox[{ RowBox[{ SqrtBox[ SuperscriptBox["3", "x"]], "-", SuperscriptBox["2", "y"]}], "\[Equal]", "7"}]}], ",", " ", RowBox[{"{", RowBox[{"x", ",", " ", "y"}], "}"}], ",", "Reals"}], "]"}]], "Input", CellChangeTimes->{3.4276540215792913`*^9}, CellID->942160119], Cell[BoxData[ RowBox[{ RowBox[{"x", "\[Equal]", "4"}], "&&", RowBox[{"y", "\[Equal]", "1"}]}]], "Output", CellChangeTimes->{3.461566851140625*^9, 3.469795184625*^9}] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 13\nHallar los valores enteros x , y, z que verifican:\n\t", Cell[BoxData[ FormBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{ RowBox[{ RowBox[{"2", "x"}], "+", RowBox[{"3", "y"}], "-", RowBox[{"5", "z"}]}], "=", "1"}]}, { RowBox[{ RowBox[{ RowBox[{"3", "x"}], "-", RowBox[{"4", "y"}], "+", RowBox[{"7", "z"}]}], "=", "3"}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], TraditionalForm]]] }], "Subsection", CellChangeTimes->{{3.427653024754302*^9, 3.427653065355845*^9}, { 3.427653866918251*^9, 3.427653913900872*^9}, {3.4276539496715517`*^9, 3.4276540065633783`*^9}, {3.427654051648344*^9, 3.427654160589184*^9}, { 3.427696286706781*^9, 3.42769638037156*^9}, {3.4276965304565496`*^9, 3.4276965320151567`*^9}, {3.4277783932809343`*^9, 3.427778395554337*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{ RowBox[{"2", " ", "x"}], "+", RowBox[{"3", "y"}], "-", RowBox[{"5", "z"}]}], "==", "1"}], "&&", RowBox[{ RowBox[{ RowBox[{"3", "x"}], "-", RowBox[{"4", "y"}], "+", RowBox[{"7", "z"}]}], "\[Equal]", "3"}]}], ",", RowBox[{"{", RowBox[{"x", ",", "y", ",", "z"}], "}"}], ",", "Integers"}], "]"}]], "Input", CellID->31436120], Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{"C", "[", "1", "]"}], "\[Element]", "Integers"}], "&&", RowBox[{"x", "\[Equal]", RowBox[{"C", "[", "1", "]"}]}], "&&", RowBox[{"y", "\[Equal]", RowBox[{"22", "-", RowBox[{"29", " ", RowBox[{"C", "[", "1", "]"}]}]}]}], "&&", RowBox[{"z", "\[Equal]", RowBox[{"13", "-", RowBox[{"17", " ", RowBox[{"C", "[", "1", "]"}]}]}]}]}]], "Output", CellChangeTimes->{3.461566851484375*^9, 3.469795184703125*^9}] }, Open ]], Cell["\<\ En este resultado C[1] representa cualquier n\[UAcute]mero entero\ \>", "Text", CellChangeTimes->{{3.427696398296101*^9, 3.427696426298965*^9}}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 14\nHallar los valores enteros de x que verifiquen:\n\ta) ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "1000"], "-", RowBox[{"2", SuperscriptBox["x", "777"]}], "+", "1"}], " ", "=", " ", "0"}], TraditionalForm]], "None"], "\n\tb) ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "5"], "-", RowBox[{"2", "x"}], "+", "1"}], "<", "0"}], TraditionalForm]], "None"] }], "Subsection", CellChangeTimes->{{3.4276966077199802`*^9, 3.427696701079441*^9}, { 3.4277784366929693`*^9, 3.427778438939822*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "1000"}], "-", RowBox[{"2", RowBox[{"x", "^", "777"}]}], "+", "1"}], "\[Equal]", "0"}], ",", "x", ",", "Integers"}], "]"}]], "Input", CellID->626380406], Cell[BoxData[ RowBox[{"x", "\[Equal]", "1"}]], "Output", CellChangeTimes->{3.461566851515625*^9, 3.469795184734375*^9}] }, Open ]], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{ RowBox[{"x", "^", "5"}], "-", RowBox[{"2", "x"}], "+", "1"}], "<", "0"}], ",", "x", ",", "Integers"}], "]"}]], "Input", CellID->50212146], Cell[BoxData[ RowBox[{ RowBox[{"x", "\[Element]", "Integers"}], "&&", RowBox[{"x", "\[LessEqual]", RowBox[{"-", "2"}]}]}]], "Output", CellChangeTimes->{3.461566851546875*^9, 3.469795184765625*^9}] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Ejemplo 15 Hallar todos los valores de x que verifican: \tcos(x) = 1/2\ \>", "Subsection", CellChangeTimes->{{3.427697777015918*^9, 3.427697815260194*^9}, { 3.427778492720381*^9, 3.427778494922214*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{"Reduce", "[", RowBox[{ RowBox[{ RowBox[{"Cos", "[", "x", "]"}], "\[Equal]", RowBox[{"1", "/", "2"}]}], ",", "x"}], "]"}]], "Input", CellID->142038859], Cell[BoxData[ RowBox[{ RowBox[{ RowBox[{"C", "[", "1", "]"}], "\[Element]", "Integers"}], "&&", RowBox[{"(", RowBox[{ RowBox[{"x", "\[Equal]", RowBox[{ RowBox[{"-", FractionBox["\[Pi]", "3"]}], "+", RowBox[{"2", " ", "\[Pi]", " ", RowBox[{"C", "[", "1", "]"}]}]}]}], "||", RowBox[{"x", "\[Equal]", RowBox[{ FractionBox["\[Pi]", "3"], "+", RowBox[{"2", " ", "\[Pi]", " ", RowBox[{"C", "[", "1", "]"}]}]}]}]}], ")"}]}]], "Output", CellChangeTimes->{3.46156685178125*^9, 3.46979518484375*^9}] }, Open ]] }, Open ]] }, Open ]], Cell[CellGroupData[{ Cell[" Sistemas de Ecuaciones Lineales", "Section 1"], Cell[TextData[{ "Sea el sistema lineal expresado en forma matricial:\n\tA.x = b\ndonde A es \ la matriz de los coeficientes, b es el vector de t\[EAcute]rminos \ independientes y x es el vector de las incognitas. si existe ", Cell[BoxData[ SuperscriptBox["A", RowBox[{"-", "1"}]]]], ", entonces la soluci\[OAcute]n del sistema es: \n\tx= ", Cell[BoxData[ SuperscriptBox["A", RowBox[{"-", "1"}]]]], "\t.b\n\nEsta es una forma de obtener la soluci\[OAcute]n del sistema. Tambi\ \[EAcute]n se pueden utilizar el comando Solve y el comando LinearSolve para \ resolver sistemas lineales.\t\n\nSiendo A la matriz de coeficientes y b el \ vector de t\[EAcute]rminos independientes, la sintaxis del comando \ LinearSolve es la siguiente:\n\tLinearSolve[A,b]" }], "Text", CellChangeTimes->{{3.4276286012876453`*^9, 3.42762864753303*^9}, { 3.45915414821875*^9, 3.459154210828125*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[TextData[{ "Ejemplo 16\nResolver la ecuaci\[OAcute]n matricial y comprobar el resultado \ obtenido:\n\t", Cell[BoxData[ TagBox[ RowBox[{"(", "\[NoBreak]", GridBox[{ {"2", RowBox[{"-", "1"}], "1"}, {"4", "1", "1"}, {"6", RowBox[{"-", "6"}], "8"} }, GridBoxAlignment->{ "Columns" -> {{Center}}, "ColumnsIndexed" -> {}, "Rows" -> {{Baseline}}, "RowsIndexed" -> {}}, GridBoxSpacings->{"Columns" -> { Offset[0.27999999999999997`], { Offset[0.7]}, Offset[0.27999999999999997`]}, "ColumnsIndexed" -> {}, "Rows" -> { Offset[0.2], { Offset[0.4]}, Offset[0.2]}, "RowsIndexed" -> {}}], "\[NoBreak]", ")"}], MatrixForm[#]& ]]], ".", Cell[BoxData[ InterpretationBox[ RowBox[{"(", GridBox[{ {"x"}, {"y"}, {"z"} }], ")"}], MatrixForm[{x, y, z}]]]], " = ", Cell[BoxData[ RowBox[{"(", "\[NoBreak]", TagBox[GridBox[{ {"1"}, {"2"}, {"3"} }, GridBoxAlignment->{ "Columns" -> {{Center}}, "ColumnsIndexed" -> {}, "Rows" -> {{Baseline}}, "RowsIndexed" -> {}}, GridBoxSpacings->{"Columns" -> { Offset[0.27999999999999997`], { Offset[0.5599999999999999]}, Offset[0.27999999999999997`]}, "ColumnsIndexed" -> {}, "Rows" -> { Offset[0.2], { Offset[0.4]}, Offset[0.2]}, "RowsIndexed" -> {}}], Column], "\[NoBreak]", ")"}]]] }], "Subsection", CellChangeTimes->{ 3.427524152946485*^9, {3.427524185506216*^9, 3.427524193295944*^9}, 3.42754118171255*^9, {3.457932044796875*^9, 3.45793204496875*^9}, { 3.4592356443125*^9, 3.459235666140625*^9}}], Cell[BoxData[{ RowBox[{ RowBox[{"A", "=", RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"2", ",", RowBox[{"-", 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RowBox[{"1", ",", "2", ",", "3"}], "}"}]], "Output", CellChangeTimes->{3.459154258046875*^9, 3.459235700328125*^9, 3.461566852078125*^9, 3.46979518490625*^9}] }, Open ]], Cell[TextData[{ "Otra forma de resolver el sistema consiste en utilizar el comando ", StyleBox["Thread", FontWeight->"Bold"], ". al aplicar el comando ", StyleBox["Thread", FontWeight->"Bold"], " a matriza.{x,y,z}=={3,-1,4}, se obtiene {3 x+2 z==3,-3 x+2 y+2 z==-1,2 \ x-3 y+3 z==4}. \nAplicando el comando Solve a cualquiera de estos dos \ resultados se obtiene la soluci\[OAcute]n del sistema, pero parece mejor el \ primero que es como debe ir el argumento de Solve." }], "Text", CellChangeTimes->{{3.427524283267989*^9, 3.427524332679995*^9}, { 3.428129460578125*^9, 3.4281294725625*^9}}, TextAlignment->Left, TextJustification->1], Cell[CellGroupData[{ Cell[BoxData[{ RowBox[{"Clear", "[", RowBox[{"x", ",", "y", ",", "z"}], "]"}], "\n", RowBox[{"sys", "=", RowBox[{"Thread", "[", RowBox[{ RowBox[{"A", ".", RowBox[{"{", 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En este caso es necesario introducir el \ vector b como un vector de tres filas y una columna de forma que tenga el \ mismo n\[UAcute]mero de filas que la matriz." }], "Text", CellChangeTimes->{{3.427525613671055*^9, 3.4275256818092537`*^9}}, TextAlignment->Left, TextJustification->1.], Cell[BoxData[{ RowBox[{ RowBox[{"A", "=", RowBox[{"{", RowBox[{ RowBox[{"{", RowBox[{"3", ",", "1", ",", "0"}], "}"}], ",", RowBox[{"{", RowBox[{"1", ",", "2", ",", "1"}], "}"}], ",", RowBox[{"{", RowBox[{"0", ",", "1", ",", "1"}], "}"}]}], "}"}]}], ";"}], "\n", RowBox[{ RowBox[{"b", "=", RowBox[{"{", RowBox[{"1", ",", RowBox[{"-", "2"}], ",", "4"}], "}"}]}], ";"}]}], "Input", CellChangeTimes->{{3.4275251080699368`*^9, 3.427525129664156*^9}, { 3.427525365566533*^9, 3.427525399333679*^9}, {3.45793169728125*^9, 3.457931705015625*^9}, 3.45915433325*^9, 3.459235795640625*^9, { 3.45923588184375*^9, 3.459235889359375*^9}}], Cell[CellGroupData[{ Cell[BoxData[ RowBox[{ RowBox[{"ampli", "=", RowBox[{"Transpose", 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