(* Content-type: application/mathematica *) (*** Wolfram Notebook File ***) (* http://www.wolfram.com/nb *) (* CreatedBy='Mathematica 6.0' *) (*CacheID: 234*) (* Internal cache information: NotebookFileLineBreakTest NotebookFileLineBreakTest NotebookDataPosition[ 145, 7] NotebookDataLength[ 30436, 745] NotebookOptionsPosition[ 12259, 394] NotebookOutlinePosition[ 28917, 693] CellTagsIndexPosition[ 28874, 690] WindowFrame->Normal*) (* Beginning of Notebook Content *) Notebook[{ Cell[CellGroupData[{ Cell["\<\ TAREA 2\.aa: DEFINICI\[CapitalOAcute]N Y REPRESENTACI\[CapitalOAcute]N DE \ FUNCIONES\ \>", "Title", TextAlignment->Center, TextJustification->0], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 1:\nDada la fracci\[OAcute]n : (", Cell[BoxData[ RowBox[{"2", "-", "x", "-", RowBox[{"2", " ", SuperscriptBox["x", "2"]}], "+", SuperscriptBox["x", "3"]}]], CellChangeTimes->{{3.4596693113125*^9, 3.4596693113125*^9}}], ")/(", Cell[BoxData[ RowBox[{ RowBox[{"-", "6"}], "+", "x", "+", RowBox[{"4", " ", SuperscriptBox["x", "2"]}], "+", SuperscriptBox["x", "3"]}]]], "), se pide:\n\ta) Descomponer en factores el numerador y denominador.\n\tb) \ Simplificarla.\n\tc) Descomponerla en fracciones parciales.\nRepetir estas \ operaciones utilizando la paleta\tALGEBRAICMANIPULATIONS. Para ello se marca \ la expresi\[OAcute]n correspondiente y se pincha en el comando de la paleta \ que se desee." }], "Subsection", CellChangeTimes->{{3.459669336078125*^9, 3.45966935559375*^9}, { 3.472559581421875*^9, 3.472559586421875*^9}}, TextAlignment->Left, TextJustification->1], Cell["\<\ En este ejercicio se utilizan los comandos de Mathematica Numerator, \ Denominator, Factor, Cancel, Simplify y Apart\ \>", "Text", CellChangeTimes->{{3.472889326678295*^9, 3.47288934253767*^9}, { 3.47288937469392*^9, 3.47288940756892*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906417171875*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 2\nDefinir f(x,y)= ", Cell[BoxData[ FormBox[ RowBox[{ SuperscriptBox["e", RowBox[{"-", RowBox[{"(", RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], ")"}]}]], RowBox[{"cos", "(", "xy", ")"}]}], TraditionalForm]]], ". Calcular f(1,0), f(a+b, a-b) . \n" }], "Subsection", CellChangeTimes->{{3.459669402734375*^9, 3.45966949084375*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906423984375*^9}] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Ejercicio 3 Definir la funci\[OAcute]n vectorial de dos variables: \t h(x,y) = { xcosy, ysinx) }. Calcular h(1,0), h(\[Pi]/2, \[Pi]/2) y h(a+b, a-b).\ \>", "Subsection", CellChangeTimes->{ 3.425712030140625*^9, {3.459669497296875*^9, 3.459669579609375*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.4729064291875*^9}] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Ejercicio 4 Representar las funciones senx, sen(2x) y sen(3x) conjuntamente en el \ intervalo [0, \[Pi]].\ \>", "Subsection", CellChangeTimes->{{3.459669590375*^9, 3.459669597015625*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906431828125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 5\nRepresentar, en primer lugar por separado y desp\[UAcute]es en \ un \[UAcute]nico gr\[AAcute]fico, \n\t- la hoja de Descartes ", Cell[BoxData[ FormBox[ TagBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{"x", "=", FractionBox[ RowBox[{"3", "t"}], RowBox[{"1", "+", SuperscriptBox["t", "3"]}]]}]}, { RowBox[{"y", "=", FractionBox[ RowBox[{"3", SuperscriptBox["t", "2"]}], RowBox[{"1", "+", SuperscriptBox["t", "3"]}]]}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], #& ], TraditionalForm]]], "\n\t- la cicloide ", Cell[BoxData[ FormBox[ TagBox[ StyleBox[ RowBox[{"{", StyleBox[GridBox[{ { RowBox[{"x", " ", "=", " ", RowBox[{"t", "-", "sint"}]}]}, { RowBox[{"y", "=", RowBox[{"1", "-", "cost"}]}]} }], ShowAutoStyles->True]}], ShowAutoStyles->False], #& ], TraditionalForm]]], "\n" }], "Subsection", CellChangeTimes->{{3.4273718528033323`*^9, 3.427371852953821*^9}, { 3.45966970790625*^9, 3.459669874875*^9}}, TextAlignment->Left, TextJustification->1], Cell["\<\ Como se trata de curvas dadas en forma param\[EAcute]trica, crearemos dos gr\ \[AAcute]ficos utilizando el comando ParametricPlot y despu\[EAcute]s los \ combinaremos con el comando GraphicsRow.\ \>", "Text", CellChangeTimes->{{3.47288948588142*^9, 3.472889604178295*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906437828125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 6\nRepresentar la superfice de ecuaci\[OAcute]n z= ", Cell[BoxData[ RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"], "-", RowBox[{"4", "y"}], "+", "4", " "}]]], " en la regi\[OAcute]n x \[Element] [-2, 2], y \[Element] [0,4]." }], "Subsection", CellChangeTimes->{{3.427371704554427*^9, 3.427371706480214*^9}, { 3.459669904765625*^9, 3.459669994609375*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906441734375*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 7\nRepresentar la superficie cuya ecuaci\[OAcute]n es:\nz=", Cell[BoxData[ FormBox[ RowBox[{ SuperscriptBox["e", RowBox[{"-", RowBox[{"(", RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], ")"}]}]], RowBox[{"sin", "(", RowBox[{ SuperscriptBox["x", "2"], "+", SuperscriptBox["y", "2"]}], ")"}]}], TraditionalForm]]], " en la regi\[OAcute]n x \[Element] [-2, 2], y \[Element] [-3, 3]." }], "Subsection", CellChangeTimes->{{3.427371866978931*^9, 3.427371867308261*^9}, { 3.459670003375*^9, 3.459670077125*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906444296875*^9}] }, Open ]], Cell[CellGroupData[{ Cell["\<\ Ejercicio 8 Representar la superficie cuya ecuaci\[OAcute]n es: z = cosy \[Times]sinx, en \ la regi\[OAcute]n: \t\tx \[Element] [-\[Pi], \[Pi]], y \[Element] [-\[Pi], \[Pi]]. Generar cuatro gr\[AAcute]ficos distintos. - El primero, p1, utilizando la opci\[OAcute]n por defecto del comando Plot3D, - El segundo, p2, utilizando la opci\[OAcute]n ColorFunction \[Rule] (White &), - El tercero, p3, en verde con la opci\[OAcute]n ColorFunction \[Rule] \ (RGBColor[0,10, 0] /.\[InvisibleSpace]{x \[Rule] #1, y \[Rule] #2} &), y - El cuarto, p4, con varias gamas de azul utilizando la opci\[OAcute]n \ ColorFunction \[Rule] (RGBColor[0,0,Abs[Cos[y]Sin[x] ]] /.\[InvisibleSpace]{x \ \[Rule] #1, y \[Rule] #2} &).\ \>", "Subsection", CellChangeTimes->{ 3.425714951109375*^9, {3.42571504434375*^9, 3.4257150585*^9}, 3.42571519553125*^9, {3.425715314*^9, 3.42571539671875*^9}, { 3.4257155118125*^9, 3.4257155185625*^9}, {3.427371872047385*^9, 3.4273718723076067`*^9}, {3.459670083078125*^9, 3.459670318546875*^9}, { 3.47256073603125*^9, 3.472560737875*^9}}, TextAlignment->Left, TextJustification->1], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906448609375*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 9\nUtilizar el comando ParametricPlot para representar la \ circunferencia:\n", Cell[BoxData[ SuperscriptBox["x", "2"]]], " - 4x + ", Cell[BoxData[ SuperscriptBox["y", "2"]]], "- 2y = 4." }], "Subsection", CellChangeTimes->{{3.4273717821080723`*^9, 3.42737178467649*^9}, { 3.427371831024078*^9, 3.427371837317422*^9}, {3.427371881474416*^9, 3.427371882383363*^9}, 3.459670357234375*^9}], Cell[TextData[{ "La ecuaci\[OAcute]n de una circunferencia de centro el punto (a, b) y de \ radio R viene dada por :\n\t", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox[ RowBox[{"(", RowBox[{"x", "-", "a"}], ")"}], "2"], "+", SuperscriptBox[ RowBox[{"(", RowBox[{"y", "-", "b"}], ")"}], "2"], "-", SuperscriptBox["R", "2"]}], "=", "0"}], TraditionalForm]]], ".\nLa ecuaci\[OAcute]n dada es : ", Cell[BoxData[ FormBox[ RowBox[{ RowBox[{ SuperscriptBox["x", "2"], "-", RowBox[{"4", "x"}], "+", SuperscriptBox["y", "2"], "-", RowBox[{"2", "y"}], "-", "4"}], " ", "=", " ", "0"}], TraditionalForm]]], ", vamos a calcular a, b y R identificando los coeficientes de estos dos \ polinomios de segundo grado. Para ello utilizaremos el comando Coefficient de \ ", StyleBox["Mathematica", FontSlant->"Italic"], " que podemos explorar previamente en la Ayuda.\n\t" }], "Text", CellChangeTimes->{{3.472890379740795*^9, 3.47289073085017*^9}, { 3.472906481796875*^9, 3.472906482890625*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.4729064753125*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 10\nRepresentar de varias formas distintas la circunferencia : ", Cell[BoxData[ RowBox[{"6", "-", RowBox[{"6", " ", "x"}], "+", SuperscriptBox["x", "2"], "-", RowBox[{"2", " ", "y"}], "+", SuperscriptBox["y", "2"]}]], CellChangeTimes->{{3.459670426984375*^9, 3.45967046653125*^9}, 3.459670505546875*^9}], " = 0." }], "Subsection", CellChangeTimes->{{3.427371820154674*^9, 3.427371827961113*^9}, { 3.4273718879318542`*^9, 3.4273718881276712`*^9}, {3.45967038425*^9, 3.459670405609375*^9}, {3.459670513265625*^9, 3.459670522109375*^9}}], Cell["\<\ La forma mas sencilla de representar la circunferencia dada es utilizando el \ comando ContourPlot. Utilizamos opciones del comando como las que representan \ los ejes y eliminan el marco. Ademas con la opci\[OAcute]n ContourStyle \ representamos la circunferencia en trazo grueso y rojo.\ \>", "Text", CellChangeTimes->{{3.472890883522045*^9, 3.472890907490795*^9}, { 3.472891001647045*^9, 3.472891026772045*^9}, {3.47289106841267*^9, 3.47289109644392*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.47290649034375*^9}], Cell["\<\ Para representar la circunferencia mediante el comando ParametricPlot hacemos \ lo mismo que en el ejercicio anterior para calcular el centro y el radio. En \ este caso, vamos a simplificar el c\[AAcute]lculo calculando unicamente el \ radio. \ \>", "Text", CellChangeTimes->{{3.472891108709545*^9, 3.472891217959545*^9}, 3.472906503953125*^9}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906500515625*^9}], Cell["\<\ Finalmente vamos a representar cada una de las ramas de la circunferencia \ despejando y en la ecuaci\[OAcute]n impl\[IAcute]cita y utilizando el comando \ Plot para generar dos gr\[AAcute]ficos que luego se muestran conjuntamente \ con el comando Show.\ \>", "Text", CellChangeTimes->{{3.472891641490795*^9, 3.47289169856892*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.47290651690625*^9}] }, Open ]], Cell[CellGroupData[{ Cell[TextData[{ "Ejercicio 11\nSea f(x) = ", Cell[BoxData[ FormBox[ SuperscriptBox["x", "2"], TraditionalForm]]], "+2x+2 y g(x) = x+1. Obtener las siguientes composicones de funciones:\n\t- \ f", Cell[BoxData[ FormBox["\[SmallCircle]", TraditionalForm]]], "f(x)\n\t- f", Cell[BoxData[ FormBox["\[SmallCircle]", TraditionalForm]]], "g(x)\n\t- g", Cell[BoxData[ FormBox["\[SmallCircle]", TraditionalForm]]], "f(x)\n\t- g", Cell[BoxData[ FormBox["\[SmallCircle]", TraditionalForm]]], "g(x)\n" }], "Subsection", CellChangeTimes->{{3.427371820154674*^9, 3.427371827961113*^9}, { 3.4273718879318542`*^9, 3.4273718881276712`*^9}, {3.45967038425*^9, 3.459670405609375*^9}, {3.459670513265625*^9, 3.459670586796875*^9}, { 3.4596706184375*^9, 3.45967068253125*^9}}], Cell[BoxData["\[IndentingNewLine]"], "Input", CellChangeTimes->{3.472906529140625*^9}] }, Open ]] }, Open ]] }, WindowToolbars->"EditBar", WindowSize->{1672, 933}, WindowMargins->{{0, Automatic}, {Automatic, 0}}, DockedCells->FEPrivate`If[ FEPrivate`SameQ[FEPrivate`$ProductIDName, "MathematicaPlayer"], FEPrivate`Join[{ Cell[ BoxData[ GraphicsBox[ RasterBox[CompressedData[" 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